Given a complex aluminum plate with a rectangular area of 64 square feet and a triangular area of 16 square feet, what is the total weight if aluminum weighs 14 pounds per square foot?

To find the total weight of the aluminum plate, you first need to determine the total area by adding the areas of the rectangular and triangular sections. The rectangular area is given as 64 square feet, and the triangular area is 16 square feet.

Calculating the total area involves the sum of these two areas:

[

\text{Total Area} = \text{Rectangular Area} + \text{Triangular Area}

]

[

\text{Total Area} = 64 , \text{sq ft} + 16 , \text{sq ft} = 80 , \text{sq ft}

]

Once the total area is established, the next step is to calculate the total weight. Since the weight of aluminum is provided as 14 pounds per square foot, you can find the total weight by multiplying the total area by the weight per square foot:

[

\text{Total Weight} = \text{Total Area} \times \text{Weight per Square Foot}

]

[

\text{Total Weight} = 80 , \text{sq ft} \times 14 , \text{lbs/sq ft} = 1,